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Serhud [2]
3 years ago
11

Sophia is 12 years old. Her Uncle Reynald tells her that if she adds 5 to her age, multiplies the sum by 3, and then subtracts 4

from the product, she will find his age. She tells him that his age equals the expression 12 + 5 × 3 − 4 .
Is Sophia correct?
Mathematics
1 answer:
Scilla [17]3 years ago
7 0
No, according to PEMDAS, that expression would be the same as saying 12+(5*3)-4, not the correct expression: (12+5)*3-4.
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The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

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12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

\bf P(t)= 10.3e^{kt}

Given that P(10)=12.5

\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

We need P(20)

\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
What is the grates common factor of 15 and 64??
Rashid [163]

Answer:

The gcf of 15 and 64 can be obtained like this: The factors of 15 are 15, 5, 3, 1. The factors of 64 are 64, 32, 16, 8, 4, 2, 1. The common factors of 15 and 64 are 1, intersecting the two sets above. In the intersection factors of 15 ∩ factors of 64 the greatest element is 1. Therefore, the greatest common factor of 15 and 64 is 1.

Hope this helped!

Good luck :p

~Emmy <3



7 0
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