1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
disa [49]
2 years ago
7

Energy in higher trophic levels is greater than energy at lower trophic levels.

Biology
1 answer:
mel-nik [20]2 years ago
4 0
<span>It is false that energy in higher trophic levels is greater than energy at lower trophic levels. In the first trophic level you find the producers, in the second the primary consumers in the level following that the secondary consumers and in the last level the tertiary consumers. And only 10% of energy at one level is available to the next level. </span>
You might be interested in
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
What would happen if everyone ate raw food only?
Juliette [100K]

Answer: they would have diarrhea, stomach cramps, vomiting, and a fever.

Explanation:

7 0
1 year ago
In sickle cell disease variation in one gene causes red blood to end or sickle this means the suckled cells ___
ivolga24 [154]
Your answer is actually idk
5 0
3 years ago
The inner membrane of the mitochondria can be compared functionally to the thylakoid membranes of the chloroplast because both c
GenaCL600 [577]

Answer:

The inner membrane of the mitochondria can be compared functionally to the

thylakoid membranes of the chloroplast because both contain a system for:

electron transport.

8 0
3 years ago
What term is associated with reproduction
My name is Ann [436]
Fertilisation maybe...........
5 0
3 years ago
Other questions:
  • All cells need energy to live. How do the organelles in the plant cell above work together to get and use this energy?
    9·2 answers
  • What is the function of the membrane that covers compact bone?
    15·1 answer
  • How do the number of muscles in a cow eye compare with that of a human eye, and what does this mean for each organism?
    5·1 answer
  • The tundra is cold year-round. it has short cool summers and long, severe winters. The tundra has a permanently frozen sublayer
    12·1 answer
  • Humans have pores in their skin to sweat and cool off the body. Plants have similar structures called _____.
    10·1 answer
  • ______ support mango trees out of the water.
    6·1 answer
  • Write a paragraph about how one would go about eradicating malaria in West Africa.
    7·1 answer
  • It was my first day in the class. I was very nervous as the college was away from my home town. I had to stay away from my paren
    7·1 answer
  • When walking her 6-year old son for school, a mother observes that the boy is limping. She notices that his left knee is swollen
    15·1 answer
  • classify each of the hypothetical experiments as double blind, single blind, or unblinded. at least one experimental technique w
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!