Ask question

Ask question

All categories

4 years ago

8

A log is reacting with oxygen as it burns in a fireplace. If the amount of oxygen reaching the log is reduced, what happens to t

he rate of this chemical reaction?

2 answers:

Aloiza [94]4 years ago

7 0

<span>the rate decreases should be your answer</span>

Komok [63]4 years ago

7 0

It decreases is the correct answer

You might be interested in

Simplify (4f+13g)(2w)

Anna35 [415]

Answer:

8fw+26gw

i think this is it

7 0

3 years ago

Read 2 more answers

Which alkane is the isomer of butane called 2-methylpropane? A skeletal model of a 4-carbon chain has a straight line extending

solmaris [256]

Answer:

A three-carbon chain has a straight line extending from the center carbon.

Explanation:

Isomers are compounds having the same molecular formula but different structural formulas.

Butane and 2-methylpropane are constitutional isomers. Constitutional isomers differ in the way that the constituent atoms are connected to each other.

Butane is a straight chain compound while the compound 2-methylpropane consists of a three-carbon chain which has a straight line extending from the center carbon.

8 0

3 years ago

Read 2 more answers

How does the energy of an electron change when the electron moves closer to the nucleus?

tankabanditka [31]

It increases. B.

Close to the nucleus are high energy levels, because of the pull of the nucleus. But farther away from the nucleus, the electrons there are of low energy level.

5 0

4 years ago

When water vapor cools it condenses select the number that represents this process on the diagram

TiliK225 [7]

2 is the correct answer.

6 0

4 years ago

Read 2 more answers

Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

3 0

3 years ago