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Sloan [31]
3 years ago
5

I need help with this please

Chemistry
2 answers:
topjm [15]3 years ago
6 0

Answer:

C. 3.14

Explanation:

That's because pi is what mathematicians call an "infinite decimal" — after the decimal point, the digits go on forever and ever. When starting off in math, students are introduced to pi as a value of 3.14 or 3.14159. Though it is an irrational number, some use rational expressions to estimate pi, like 22/7 of 333/106

Naddik [55]3 years ago
5 0

Answer:

3

Explanation:

If we want it to be rounded to one significant figure, it will be 3.

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Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
o-na [289]

Answer:

vHe / vNe = 2.24

Explanation:

To obtain the velocity of an ideal gas you must use the formula:

v = √3RT / √M

Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio is:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

<em>vHe / vNe = 2.24</em>

<em />

I hope it helps!

8 0
3 years ago
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Marizza181 [45]

Answer:

That's simple it's the caca of 54 32 x (5) b ÷ 5683jvl done so your answer is 0

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Which in the following best describe carbon
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I just know it’s not conductive or brittle
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How does the value of kc in n2o4(g)⇋2no2(g) kc=[no2]2[n2o4] depend on the starting concentrations of no2 and n2o4?
Vlad [161]
<h3><u>Answer;</u></h3>

The value of Kc does not depend on starting concentrations.

<h3><u>Explanation;</u></h3>
  • <em><u>At constant temperature, changing the equilibrium concentration does not affect the equilibrium constant, because the rate constants are not affected by the concentration changes. </u></em>
  • When the concentration of one of the participants is changed, the concentration of the others vary in such a way as to maintain a constant value for the equilibrium constant.
8 0
4 years ago
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