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3 years ago

Help me with this pls pls pls

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

3 1/2
Becase if you turn them both in to inporper fractions then you can do other sh1t to find it out

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Do all digits in number 333 have the same value

postnew [5]

No. the first 3 is 300, the second 3 is 30, and the third 3 is 3

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1 year ago

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Match each organ or function with its body system <br><br> Excretory and digestive are the options

Tresset [83]

Answer:

digestive would be stomach, excretion is the big and small intestines

Step-by-step explanation:

stomach digests food, your intestines process whatever is left till you excrete

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3 years ago

What is the fourth term in the binomial expansion of (2x – y) 7?

nata0808 [166]

Answer:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

Step-by-step explanation:

For this case we have the following expression:

$(2x-y)^7$

And we can use the binomial theorem given by:

$(x+y)^n =\sum_{k=0}^n (nCk) x^k y^{n-k}$

And for this case we want to find the fourth term and using the formula we have:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

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2 years ago

The school that Stephen goes to is selling tickets to a choral performance on the first day of tickets sells the school so three

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2 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$