This is an arithmetic sequence with first term (a) = 11, number of terms (n) = 57, sum of nth term (Sn) = 19,779.
Let the amount of money she saved more each month be d, then
Sn = n/2(2a + (n - 1)d)
19,779 = 57/2(2(11) + (57 - 1)d)
19,779 = 28.5(22 + 56d)
19,779 = 627 + 1,596d
19,779 - 627 = 1,596d
d = 19,152/1,596 = 12
Therefore, she saved $12.00 more each month.
Answer:
False. See explanation below.
Step-by-step explanation:
False
A simple random sample "is a subset of a statistical population in which each member of the subset has an equal probability of being chosen"
In other words that means in order to apply a random sampling we need to ensure that we have the same probability of inclusion for every possible element of the population of interest.
And for this case a collection of any numerical information is not referred as random sampling since we don't know if these scores are representative of the population of interest.
And we don't know if this information is obtained using any sampling frame or sampling methodology.
2 3/10 = 2.3
To get this number as a percent, we need to multiply it by 100: 2.3 is a whole number, and can be represented by fraction 2.3/1
A percentage is represented by a fraction over 100. So to transform 2.3/1 to a percentage, just multiply both numerator and denominator by 100, and you'll get 230/100.
So 2 3/10 is 230% as a percent.
Hope this Helps! :)
The answer 0.6 i apologize if it is incorrect!