The sum of two integers is greater than 12. One integer is 10 less than the other. What are the values of the integers?
1 answer:
Let's set up an equation: x plus y is greater than 12 x + y > 12 One of the integers is ten less than twice the other one x = 2y -10 Time to start solving: (2y-10) + y > 12 2y + y > 12 + 10 3y > 22 3y=24 y=8 Now its time to find the value of x: x=2(8) - 10 x=16-10 x= 66 + 8 > 12, 6+8 is greater than twelve. In conclusion we can wrap up that 6 and 8 are the least value integers.
You might be interested in
3x + 6 distribute the 3 to both of the places in the parentheses.
Use the distributive formula
a(b - c) = ab - ac
Answer:
f(x) = (x + 8)² -6
Answer:
3.33333333333+1/3=3.6666666666666666
The answer would be 2(6x+5+2y) you can figure this out through the distributive property. 2(6x)=12x 2(5)=10 and 2(2y)= 4y this would reult in giving you the equation 12x+10+4y