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2 years ago

9

There are 6 red marbles, 8 blue marbles, and 11 green marbles in a bag. What is the probability that you

1 answer:

Kay [80]2 years ago

7 0

Answer:

14/25

Step-by-step explanation:

p(red or blue)=6/(6+8+11) +8/(6+8+11)=6/25+8/25=14/25

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$\huge\text{Hey there!}$

$\huge\textbf{Equation:}$

$\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\huge\textbf{Solve:}$

$\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

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$\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\huge\textbf{Simplify it:}$

$\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}$

$\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}$

$\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}$

$\huge\textbf{Simplify it:}$

$\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}$

$\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}$

$\mathbf{\rightarrow x = \dfrac{45}{20}}$

$\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}$

$\mathbf{\rightarrow x = \dfrac{9}{4}}$

$\mathbf{x \approx 2 \dfrac{1}{4}}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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