We are asked to express the diagonal of a rectangle in terms of the width in which the area of the polygon is equal to 13 square feet. The area of teh rectangle is equal to length times width. That is 13 = lw; diagonal using pythagorean theorem is sqrt ( l2 + w2). Thus d = sqrt ( (13/w)2 + w2) = sqrt ( (169/w2 + w2) = sqrt ( (169 + w4)/w2) = 1/w sqrt (169 + w4)
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It's not possible to answer the question with the information provided, you will need to post the ratios in the problem.
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200 in all
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-9df^3 - 3f^3 - 7d^2 - 8d - 15625
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