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2 years ago

What is the solution to the rational equation x over 2x minus 1 minus 1 over 4 equals 2 over 2x minus 1 ? (1 point)

Mathematics

1 answer:

Volgvan2 years ago

3 0

I think the answer is x = 7 over 6

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Help find the area, please.

Tanzania [10]

The answer is 72 !! :)

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3 years ago

What is a possible value of sin(x) if the cos(2x) = 0.42

Ostrovityanka [42]

Answer:

The answer is 0.54 have a great day

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3 years ago

A particular amuesment park ride will make 150 revolitions in 180 seconds at this rate how many revolutions will it make in 2 mi

ASHA 777 [7]

Answer:

100 revolitions

Step-by-step explanation:

180s = 3min

50s = 1min

50 * 2 = 100

7 0

2 years ago

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Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .

$\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2$ .

$\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2$ .

Solve this equation for $u$ :

$\displaystyle \frac{u^{2} + 1}{u^{2}} = 2$ .

$u^{2} + 1 = 2 u^{2}$ .

$u^{2} = 1$ .

Given that $0 \le u \le 1$ , $u = 1$ is the only possible solution.

$\cos^{2}{x} = 1$ ,

$x = k \pi$ , where $k\in \mathbb{Z}$ (i.e., $k$ is an integer.)

Given that $0 \le x < 2\pi$ ,

$0 \le k$ .

$k = 0$ or $k = 1$ . Accordingly,

$x = 0$ or $x = \pi$ .

8 0

2 years ago

Read 2 more answers

The angles below are supplementary. What is the value of x?

USPshnik [31]

Since the angles are supplementary, we know that they must add up to equal 180 degrees by the definition of supplementary angles

set the sum of the 2 angles to equal 180 and solve for x

6x + 48 + 60 = 180
6x + 108 = 180
6x = 72
x = 12

you could check to make sure that your x value is correct by plugging it back into the equation

6(12) + 48 + 60 = 180
72 + 48 + 60 = 180
120 + 60 = 180
180= 180

hope this helped!

8 0

3 years ago