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raketka [301]
3 years ago
10

A restaurant offers a​ $12 dinner special that has 77 choices for an​ appetizer, 1010 choices for an​ entrée, and 44 choices for

a dessert. how many different meals are available when you select an​ appetizer, an​ entrée, and a​ dessert?
Mathematics
1 answer:
krok68 [10]3 years ago
5 0
<span>280 I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre, so the number of possible meals to this point is n = 7 * 10 = 70 Finally, you finish off with a dessert, so the number of meals is: n = 70 * 4 = 280 Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is n = 77 * 1010 * 44 = 3421880 But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
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Answer:

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hope this helps

have a good day :)

Step-by-step explanation:

4 0
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5 0
3 years ago
Express 15.16 as a mixed number
kap26 [50]
If this is not a typo, and you mean 15.16 as in 15 and 16 hundredths, we can express this into a mixed number.
Mixed numbers are a whole number with the remainder of that number as a fraction.
For example, 1.25 as a decimal = 1 1/4 as a mixed number.
Since we already have our whole number, 15, we need to know what 16 hundredths is simplified as a fraction.
Currently, our mixed number is 15 16/100.
To simplify this, we need to find a common factor that 16 and 100 share.
Since they are both even numbers, let's divide by 2.
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Our new mixed number is 15 8/50.
Currently our fraction is still even, so divide by 2 again.
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Your new mixed number is 15 4/25.
4 and 25 have no common factors, so the fraction is simplified.
Your answer is:
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I hope this helps!
4 0
3 years ago
Read 2 more answers
if there are 2040 seats in a section of a stadium, 20 seats in the first row, and 4 more seats in each row, how many rows are th
Lorico [155]


2040 = n/2(20+(n-1)4)

4080 = n(20+4n-4)

4080= 20n +4n^2 -4n

1020 = 4n + n^2

n^2 +4n -1020 =0

use common formula (can't write out so just look at answers. sorry)

which gives answers of n=-34 and n=30. since n can only be positive, n=30 so there are 30 rows. I liked that challenge

5 0
3 years ago
Read 2 more answers
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