Answer:
As ΔABC is an <u>isosceles triangle</u>:
⇒ BA = BC
(the dashes on the line segments indicate they are of equal measure)
⇒ ∠BAC = ∠BCA = 55°
⇒ ∠BCA = ∠BAD = 55°
Angles on a <u>straight line</u> sum to 180°
⇒ ∠ADE + ∠EDC = 180°
⇒ 98° + ∠EDC = 180°
⇒ ∠EDC = 82°
As BE intersects AC, the <u>vertically opposite angles</u> are <em>equal</em>:
⇒ ∠BDC = ∠ADE = 98°
⇒ ∠ADB = ∠EDC = 82°
Interior angles in a triangle sum to 180°
⇒ ∠BAD + ∠ADB + ∠ABD = 180°
⇒ 55° + 82° + ∠ABD= 180°
⇒ ∠ABD = 180° - 55° - 82°
⇒ ∠ABD = 43°
SinA=8/17, so arcsin(8/17) is your angle of A (around 49 degrees). 90-A is your angle for B
Answer:
The slope is y=0.59x so 0.59
The y intercept is 0
Answer:
43.75 ft²
Step-by-step explanation:
= (l√(w/2)² + h²) + (w√(l/2)² + h²)
l & w become 3.5, and h becomes 6.
<em /><em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)
<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>
<em /> = 2(3.5√(3.5/2)² + 6²)
<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>
<em /><em> </em>= 2(3.5√1.75² + 6²)
<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>
= 2(3.5√3.0625 + 36)
<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>
<em /> = 2(3.5√39.0625)
<em>Step 5: The square root of 39.0625 is 6.25.</em>
<em /><em> </em>= 2(3.5 * 6.25)
<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>
<em /> = 2(21.875)
<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>
<em /> = 43.75 ft²
The lateral area of this pyramid is 43.75 ft².
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