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Studentka2010 [4]
2 years ago
9

What is the length of leg y of the right triangle?

Mathematics
2 answers:
belka [17]2 years ago
6 0
Y= 12

I'm sayin 12, hope it helps

denis23 [38]2 years ago
6 0
Using the formula, a^{2}+b^{2}=c^{2}, we can solve this problem. The hypotenuse is 37.
37^2-35^2=\sqrt{144}
\sqrt{144}= 12
The answer is 12
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Graph the inequality. 3x+4y>20
gogolik [260]

Answer:

y=-3/4x+5

Step-by-step explanation:

3x+4y>20

4y>-3x+20

y>-3/4x+5

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2 years ago
A copy machine makes 84 copies in 3 minutes and 30 seconds. How many copies does it make per minute
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24

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3 years ago
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2 years ago
How do you reduce 75/100?
Anestetic [448]
Find the greatest common factor and then divide each number by it. 

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75 divided by 25 = 3
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4 0
3 years ago
Read 2 more answers
Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t
Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3  6  10  12  15

2 | 3  3   5   6  15

3 | 3  3   5   3  15

5 | 1    1  5   1    5

  | 1    1   1   1     1

LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5

LCM(3, 6, 10, 12,15)=60

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0
2 years ago
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