<span>(-yx^2)^2 • -2x^0y^3
= x^4y^2 (-2y^3)
= - 2x^4y^5</span>
Answer:
3 (a/3) = a
Step-by-step explanation:
a/3 + a/3 + a/3
3 times a/3
the 3's cancel each other out
A
Keep up the good work! =)
Answer:
The mold will cover half the area as much are one day before it.
Step-by-step explanation:
Given:
Every day the mold on bread grows doubles
And by 8th day entire bread covered with it.
To Find:
When was half the bread covered by mold.
Solution:
It is said that area covered by mold doubles on each day
Total days taken to cover entire bread are 8
Let Area of bread be A
So Area covered (A) corresponds to 8 days with doubling.
So on previous day it should What ever area on 8th day/2
i.e A(8)/2
Similar on 6th day A(7)/2
So on 5ht day =A(6)/2 ,4th= A(5)/2, on 3rd= A(4)/2, on 2nd=A(3)/2
On 1st =A(2)/2
So we required Area= half of total.
<em>One day before the 8th day will be 7th day</em>
<em>on that day it will cover half are so that on next day will cover the double of the previous area consumed.</em>
Let's begin by breaking each number down into its prime factors: 4 = 2 x 2 5 = 5 6 = 2 x 3 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4, 5, and 6 by multiplying all common and unique prime factors of each number: common prime factors: 2 unique prime factors: 2,5,3 LCM = 2 x 2 x 5 x 3 = 60 Next, let's determine how many times 60 goes into 10,000 (excluding remainder): 10,000/60 = 166 and 2/3 Multiples of ALL 3 numbers (4,5,6) = 166 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4 and 5 by multiplying all common and unique prime factors of each number: common prime factors: none
unique prime factors: 2 x 2 x 5
LCM = 2 x 2 x 5 = 20 Next, let's determine how many times 20 goes into 10,000:
10,000/20 = 500
Multiples of BOTH numbers (4 and 5) = 500 Finally, let's subtract the multiples of ALL three numbers (4,5,6) from the multiples of BOTH numbers (4 and 5) to get our answer: Multiples of ONLY numbers 4 and 5 (excluding 6): 500 - 166 = <span>334</span>
