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amm1812
3 years ago
7

I'm very confused on this question and I don't know how to solve it. Any kind of help will be appreciated.

Mathematics
1 answer:
juin [17]3 years ago
6 0

QP is the bisector so QPM is half NPM or

m \angle NPM = 2 m \angle QPM


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CAN SOMEONE GIVE ME A HELPING HAND WITH THIS PLEASE? THANK YOU FOR YOUR TIME <br> STATISTICS
choli [55]

Answer:

B and C

Step-by-step explanation:

Cluster means points in data that spike separately like "little hills", which you can see in B and C.

3 0
3 years ago
Please help me ASAP I need it done by 2:30 please help I beg you
Galina-37 [17]

Answer:

148.619957seconds

Step-by-step explanation:

C=2 times pi times r

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700=3.14 times r

r=222.929936

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5 0
3 years ago
In T-ball, the distance to each successive base is 50 feet. If the distance from home plate to the pitcher’s mound is 38 feet, h
JulijaS [17]

Answer:

<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>

Step-by-step explanation:

The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.

We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

50^{2} =38^{2}+x^{2}\\x^{2}=50^{2}-38^{2}\\x=\sqrt{2500-1444}\\ x=\sqrt{1056}\\ x \approx 32.5 \ ft

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.

Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

50^{2}=32.5^{2}+y^{2}\\y^{2}=50^{2}-32.5^{2}\\y=\sqrt{2500-1056.25}\\ y =\sqrt{1443} \approx 37.99

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.

<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>

8 0
3 years ago
 The cost of petrol rises by 2 cents a liter. last week a man bought 20 liters at the old price. This week he bought 10 liters a
Allushta [10]
I think the answer would be $3.06.
7 0
3 years ago
HELP PLS
olchik [2.2K]

3996  \times  \frac{1}{3}  = 1332
the volume is 1332 in^3


good luck
4 0
3 years ago
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