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zaharov [31]
3 years ago
5

Which algebraic expression models the given word phrase? 6 times the sim of a and b

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0
The answer is 6(a + b)
Hope this helps.
Brainliest Please!
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Which statement describes the function y = axn when a = 1 and n is odd?
kiruha [24]

Answer:

The graph is symmetric about the origin.

The graph does not pass through the origin.

Step-by-step explanation:

We're given:

  • the function y=axn
  • a = 1
  • n is odd

Because a = 1, then the given function can be rewritten as y = n.

  • The graph opens down

The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.

  • The graph is symmetric about the origin.

This is true, given the graph is a horizontal line.

  • The graph does not pass through the origin.

This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.

  • The graph has more than one x-intercept.

This would only be true when n = 0, and this isn't possible. So, no.

4 0
2 years ago
Read 2 more answers
24 inches per minute converts to how many miles per day
12345 [234]

Answer:

0.545455

Step-by-step explanation:

3 0
3 years ago
Explain why you cannot factor the trinomial x(to the power of 2)−12x+6
Vladimir [108]

Answer:

See below

Step-by-step explanation:

You cannot find two whole number integers that give a sum of -12 and a product of 6.

-1 + -11 = -12, but (-1)(-11) = 11, which isn't 6

-2 + -10 = -12, but (-2)(-10) = 20, which isn't 6

...and so on...

4 0
2 years ago
Read 2 more answers
√200 in consecutive integers and in simplified form
myrzilka [38]
√200 = √2·100 = √2 · √100 = 10√2
4 0
3 years ago
List the angles in triangle QRS from smallest to largest.
schepotkina [342]

Answer:

angle R

Step-by-step explanation:

To solve this we will use cosine rule

Cosine rule

cos(A) = \frac{b^{2}+c^{2}-a^{2}}{2bc}

suppose,

q = 6.25

s = 11.04

r = 13.19

angleQ = cos^{-1}(\frac{13.19^{2}+11.04^{2}-6.52^{2}}{2(13.19)(11.04)})

            = 30.58

angleR = cos^{-1}(\frac{6.52^{2}+11.04^{2}-13.19^{2}}{2(6.52)(11.04)})

            = 93.82

angleS =  cos^{-1}(\frac{6.52^{2}+13.19^{2}-11.04^{2}}{2(6.52)(13.19)})

            = 56.63

4 0
3 years ago
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