Answer:
16.2 J
Explanation:
Step 1: Given data
- Specific heat of liquid bromine (c): 0.226 J/g.K
- Volume of bromine (V): 10.0 mL
- Initial temperature: 25.00 °C
- Final temperature: 27.30 °C
- Density of bromine (ρ): 3.12 g/mL
Step 2: Calculate the mass of bromine
The density is equal to the mass divided by the volume.
ρ = m/V
m = ρ × V
m = 3.12 g/mL × 10.0 mL
m = 31.2 g
Step 3: Calculate the change in the temperature (ΔT)
ΔT = 27.30 °C - 25.00 °C = 2.30 °C
The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.
Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine
We will use the following expression.
Q = c × m × ΔT
Q = 0.226 J/g.K × 31.2 g × 2.30 K
Q = 16.2 J
Answer:
Keq=0.866
Explanation:
Hello,
In this case, the undergone chemical reaction is:
In such a way, since 0.0055 mol of N₂O₄ remains in the flask, one infers that the reacted amount (
) was:
In addition, the produced amount of NO₂ is:
Finally, considering the flask's volume, the equilibrium constant is then computed as follows:
Best regards.
Answer:
John Dalton
Explanation:
John Dalton (1766-1844) is the scientist credited for proposing the atomic theory. This theory explains several concepts that are relevant in the observable world.
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Answer: HBr + NaOH = nabr + h2o
Explanation:
I hope this helped!
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- Zack Slocum
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Answer:
For water to change from a liquid to a gas, thermal energy needs to be added.
Explanation:
