Answer:
An organism that is completely composed D amino acids cannot survive.
Explanation:
Most of amino acids in all organism are present in L conformation.As result in all organism the enzymes are specific for L amino acids but not for D amino acids.
Bacterial cell wall contain some D amino acids such as D glutamate,D alanine but not entirely composed of D amino acids.
Answer:
26.25 mL
Explanation:
This is a dilution problem. First, let us calculate the volume of final solution needed:
The dog weighs 50 pounds and the sedative is administered at 0/7 ml per pound. Hence:
50 x 0.7 = 35 mL
A total volume of 35 mL, 2.5% solution of the sedative will be needed.
But 10% solution is available. There needs to be a dilution with saline water, but what volume of the 10% solution would be diluted?
initial volume = ?
final volume = 35 mL
initial concentration = 10%
final concentration = 2.5%
Using dilution equation:
initial concentration x initial volume = final concentration x final volume
initial volume = ![\frac{final concentration*final volume}{initial concentration}](https://tex.z-dn.net/?f=%5Cfrac%7Bfinal%20concentration%2Afinal%20volume%7D%7Binitial%20concentration%7D)
= 2.5 x 35/10 = 8.75 mL
Hence, 8.75 mL of the 10% pre-mixed sedative will be required.
But 35 mL is needed? The 8.75 mL is marked up to 35 mL with saline water.
35 - 8.75 = 26.25 mL
<em>Therefore, 26.25 mL of saline water will be added to 8.75 mL of the 10% pre-mixed sedative to give 2.5%, 35 mL needed for the dog.</em>
The balanced equation for the above reaction is as follows;
2Ca + O₂ ---> 2CaO
stoichiometry of Ca to O₂ is 2:1
we first need to find the limiting reactant
number of Ca moles - 6.84 mol
number of O₂ moles - 4.00 mol
if Ca is the limiting reactant
if 2 mol of Ca reacts with 1 mol of O₂
then 6.84 mol of Ca reacts with - 6.84 / 2 = 3.42 mol of O₂
this means that Ca is the limiting reactant and O₂ is in excess
therefore amount of CaO produced depends on amount of limiting reactant present
stoichiometry of Ca to CaO is 2:2
number of moles of Ca reacted = number of CaO moles formed
number of moles of CaO formed - 6.84 mol
answer is 6.84 mol