Answer:
82.416 g of KNO
₃ is needed to produce 510.0 mL of a 1.6 M KNO
₃ solution.
Explanation:
Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?
moles= 0.816
Being the molar mass of the elements:
- K: 39 g/mole
- N: 14 g/mole
- O: 16 g/mole
So the molar mass of the compound KNO₃ is:
KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole
Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?
mass= 82.416 grams
<u><em>82.416 g of KNO
₃ is needed to produce 510.0 mL of a 1.6 M KNO
₃ solution.</em></u>
Answer:
Equilibrium constant for the reaction is 0.0892
Explanation:
This is the reaction of equilibrium
H₂O + Cl₂O ⇄ 2HClO
Eq 0.077M 0.077M 0.023M
Let's make the expression for Kc
Kc = [HClO]² / [Cl₂O] . [H₂O]
Kc= 0.023² / 0.077 . 0.077 = 0.0892
Answer:
C: Sodium chloride
Explanation:
Common salt is gotten when sodium atoms reacts with chlorine atoms in an exothermic reaction to form an ionic substance known as sodium chloride with the chemical formula NaCl.
Equation is;
2Na + Cl2 = 2NaCl
Looking at the options, the correct one is Sodium chloride.
<em>A: Endoplasmic Reticulum, Chloroplasts </em>
Hoped this helped have a nice day
Answer:
First, you have to analyze your problem or question. After you research and collect data about your topic, create a hypothesis to test to try and find the answer. After testing your hypothesis, come up with a conclusion based on the results.
