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Zepler [3.9K]
4 years ago
9

2x-y-z=4, -x+2y+z=1, 3x+y+z=16. Please help

Mathematics
1 answer:
tangare [24]4 years ago
6 0
1. X=2+1/2y+1/2z

2. X=-1+2y+z

3. X=16/3-1/3y-1/3z
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Lisa wants to use her calculator to square a two-digit positive integer, but she accidentally enters the tens digit incorrectly.
Svetradugi [14.3K]

Answer: Correct two digit number= 24

Step-by-step explanation:

Let

x= tens digit (wrong one)

and y= zeroes digit

and z= tens digit (right one)

Now according to the statement,

(10x+y)² -  (10z+y)² = 2340

Simplifying this we get

(x-z)(5x+y+5z)= 117= 1 * 3 * 3 * 13

So it could either be

x-z=1 or x-z=3

If we take the x-z=1

then 5x+y+5z=117

which is not possible as maximum value we can get from this is 99.

This leaves us with x-z=3

so 5x+y+5z= 39

Put x=3+z

We get,

y+10z= 24

Now as y and z both are single digits so the only possible numbers to fit these are y=4 and z=2.

Put z=2 in x=3+z , we get x=5

So the numbers become 10x+y= 54

and 10z+y= 24

Their sum is 54+24=78

Check

54²-24²= 2340 so it is correct.

7 0
3 years ago
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zimovet [89]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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