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kakasveta [241]
3 years ago
9

The temperature at​ 8:20 P.M. is 3degreesC. If it has dropped 1degreesC per​ minute, what was the temperature at 7 : 50 ​P.M.?

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

33°C

Step-by-step explanation:

The time between 8:20 and 7:50 is 30 minutes. If it drops 1°C per minute you multiply this number by the amount of minutes which would be 30. This becomes 30°C. Then add the 3° it's at now to become 33°C.

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Answer:

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Step-by-step explanation:

Since we have to use the complete the square method, we first need to <u>rewrite the equation</u> in the form x^{2}+2ax+a^{2}=(x+a)^{2}.

This results in x^{2} + 14x + 7^{2} = 15 + 7^{2}.

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<u>Factoring </u>the left side gives us (x+7)^{2} = 64.

Finally we <u>solve the equations</u>: x+7=\sqrt{64} and x+7=-\sqrt{64}.

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