Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:
0
Step-by-step explanation:
just put in 5 for x
The range of the function y = -x² - 3x when the domain is {-5,0,2} is:
{-10, 0}.
<h3>What is the range of a function?</h3>
The range of a function is the set that contains the output values for the given domain of the function.
In this problem, the domain is:
{-5,0,2}.
Hence the output values are:
- -(-5)² - 3(-5) = -25 + 15 = -10.
- -(2)² - 3(2) = -4 + -6 = -10.
Hence the range is:
{-10, 0}.
-10 repeats, but goes only once on the range.
More can be learned about the range of a function at brainly.com/question/10891721
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Answer:
16x+19
Step-by-step explanation:
i might be wrong and its gonna take so long to explain it
Answer:
Costa Rica
Step-by-step explanation:
