All categories

3 years ago

Simplify [view attached image]

Mathematics

1 answer:

pav-90 [236]3 years ago

6 0

Given:

The given expression is $(\sqrt{5})( \sqrt[3]{5})$

We need to simplify the given expression.

Simplification:

Let us simplify the given expression.

Rewriting the given expression, we have;

$5^{\frac{1}{2}} \cdot 5^{\frac{1}{3}}$

Let us apply the exponent rule $\:a^b\cdot \:a^c=a^{b+c}$ , we get;

$5^{\frac{1}{2}+\frac{1}{3}}$

Taking LCM, we have;

$5^{\frac{3+2}{6}}$

Simplifying, we get;

$5^{\frac{5}{6}}$

Thus, the simplified value of the given expression is $5^{\frac{5}{6}}$

Hence, Option a is the correct answer.

You might be interested in

I need help thank you

erma4kov [3.2K]

Answer:

≈ 5

Step-by-step explanation:

You can use the Pythagorean Theorem to solve this:

$a^{2} + b^{2} = c^{2}$

Now plug in the numbers into the formula:

$6^{2} + b^{2} = 8^{2}$

36 + $b^{2}$ = 64

Subtract 36 from both sides:

36 + $b^{2}$ = 64

-36 -36

_________

$b^{2}$ = 28

Square both sides:

$\sqrt{b^2} = \sqrt{28}$

b = 5.29

b ≈ 5

4 0

3 years ago

Can someone plz help me !!!!!!!!

ASHA 777 [7]

1.) It's a parallelogram
area:
3.5 x 5.8 = 20.3
perimeter:
4 + 4 + 5.8+5.8 = 19.6
2.)It's a right triangle
 area:
 (6.92 x 11) ÷ 2 = 38.06
 perimeter:
 6.92 + 11 + 13 = 30.96
3.) ...that looks like a square tbh xD
area:
4.4 x 3 = 13.2
perimeter:
2.4
4.) Trapezoid

3 0

3 years ago

Which linear equation represents a

Naddika [18.5K]

Answer:

Step-by-step explanation:

The equation representing a proportional relationship is

y = kx ← k is the constant of proportion

The only equation in this form is

y = 24x ( k = 24 ) → A

7 0

3 years ago

Read 2 more answers

The opponents of soccer team A are of two types: either they are a class 1 or a class 2 team. The number of goals team A scores

NikAS [45]

Answer:

a) The expected number of goals team A will score is 5.1

b) The probability that team A will score a total of 5 goals is 0.1147

Step-by-step explanation:

Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also

E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1

b) In order for X to be equal to 5 we have 5 possibilities

- X1 is 0 and X2 is 5

- X1 is 1 and X2 is 4

- X1 is 2 and X2 is 3

- X1 is 3 and X2 is 2

- X1 is 4 and X2 is 1

- X1 is 5 and X2 is 0

Let T1 be a poisson distribution with mean λ = 2, then

$P(T1=0) = e^{-2}$

$P(T1=1) = 2 * e^{-2}$

$P(T1=2) = 2 * e^{-2}$

$P(T1=3) = \frac{4}{3} \, e^{-2}$

$P(T1=4) = \frac{2}{3}\, e^{-2}$

$P(T1=5) = \frac{4}{15}\,e^{-2}$

Lets do the same with a Poisson distribution T2 with mean λ = 3

$P(T2=0) = e^{-3}$

$P(T2=1) = 3 \, e^{-3}\\P(T2=2) = \frac{9}{2} \, e^{-3}\\P(T2=3) = \frac{9}{2} \, e^{-3}\\P(T2=4) = \frac{27}{8} \, e^{-3}\\P(T2=5) = \frac{81}{40} \, e^{-3}$

Now, we are ready to compute the probability that X is equal to 5.

$P(X1 = 0, X2 = 5) = (0.6* e^{-2} + 0.4*e^{-3}) * (0.3*\frac{4}{15}e^{-2} + 0.7*\frac{81}{40} e^{-3}) = 0.00823\\P(X1 = 1, X2 = 4) = (0.6* 2e^{-2} + 0.4*3 e^{-3}) * (0.3*\frac{2}{3}e^{-2} + 0.7*\frac{27}{8} e^{-3}) = 0.03214\\P(X1 = 2, X2 = 3) = (0.6* 2e^{-2} + 0.4*\frac{9}{2}e^{-3}) * (0.3*\frac{4}{3}e^{-2} + 0.7*\frac{9}{2} e^{-3}) = 0.05317\\P(X1 = 3, X2 = 2) = (0.6* \frac{4}{3}e^{-2} + 0.4*\frac{9}{2}*e^{-3}) * (0.3*2e^{-2} + 0.7*\frac{9}{2} e^{-3}) = 0.0471$

$P(X1 = 4, X2 = 1) = (0.6* \frac{2}{3}e^{-2} + 0.4*\frac{27}{8}e^{-3}) * (0.3*2e^{-2} + 0.7*3e^{-3}) = 0.0225\\P(X1 = 5, X2 = 0) = (0.6* \frac{4}{15}e^{-2} + 0.4*\frac{81}{40}e^{-3}) * (0.3*e^{-2} + 0.7*e^{-3}) = 0.0047$

We can conclude that

P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147

The probability that team A will score a total of 5 goals is 0.1147

7 0

3 years ago

Hello again! I need help with this question!

otez555 [7]

Answer:

(f o g) = -5x+22

Step-by-step explanation:

f o g basically means f(g(x))

So:

f(g(x)) = -5(x-4)+2

f(g(x)) = -5x+20+2

f(g(x)) = -5x+22

Therefore: (f o g) = -5x+22

This is called function composition. Basically, the output of g(x) goes into the input of f(x).

5 0

3 years ago