(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9
(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9
That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.
Thus, we obtain 3*y^12 (answer)
Please do the next one, asking questions if need be, and showing your work.
Answer:
D. dA/dt = 4h dh/dt in²/sec
Step-by-step explanation:
Given:
A = wh
w = 2h
Substitute:
A = 2h²
Take derivative with respect to time:
dA/dt = 4h dh/dt
dA/dt has units of in²/sec.
Answer:
4/5 = 80% and 8/10 = 80%
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the horizontal distance is x
<u>Use tangent to solve this:</u>
- tan 30° = 6/x
- x = 6 / tan 30°
- x = 10.4 mi (rounded)
(x-1)(x-9)
Hope this helps