Answer:
y = 1/10x
Step-by-step explanation:
We see that it intersects points (60,6), (120,12), and (0,0)
y = mx + b
m = 6/60 = 1/10
b = 0
y = 1/10x
your answer would be 147°
solution:
since ∠x and ∠y are supplementary angles. they must add up to 180°
so ∠+∠y=180°
∠x=180°-∠y
= 180°- 33°
=147
Answer:
x = 82°
y = 59°
z = 39°
Step-by-step explanation:
∠x = 1/2(134° + 30°) = 82°
∠z = 180° - 59° - 82° = 39°
arc DF = 2(39°) = 78°
arc DB + arc DF = 134° + 78° = 212°
draw a diameter down from point B to the opposite side of the circle, call that point P:
arc BDP = 180°
(arc BDF) 212° - 180° = 32° (arc PF)
∠PBG = 1/2(32°) = 16°
∠DEB = 1/2(134°) = 67°
∠DBE = 180° - 59° - 67° = 54°
(∠DBE) 54° - (∠z) 39° + (∠PBG) 16° = (∠PBE) 31°
y = 90°- 31° = 59°
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
