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riadik2000 [5.3K]
3 years ago
5

Simplify 15 + 6(x + 1).

Mathematics
2 answers:
expeople1 [14]3 years ago
5 0
The answer is: 6x+21
sweet-ann [11.9K]3 years ago
3 0
15+6x+6
6x+21

I can explain if needed
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HELP FAST!!
Vera_Pavlovna [14]

Answer:

\frac{16}{12} =1\frac{1}{3}

1\frac{5}{8}= \frac{13}{8}

3 0
3 years ago
-1/2 + ( 3/4 x 4/9)
SIZIF [17.4K]

Answer:

-1/6

Step-by-step explanation:

-1/2 + ( 3/4 x 4/9)

PEMDAS says parentheses first

Rearranging the fractions

-1/2 + ( 3/9 x 4/4)

-1/2 + (1/3*1)

-1/2 + 1/3

Getting a common denominator of 6

-1/2 *3/3 + 1/3 *2/2

-3/6+2/6

-1/6

5 0
3 years ago
How many milliliters are in 12.34 liters?
NNADVOKAT [17]

Answer:

12,340 mL

Step-by-step explanation:

12.34 L x 1000= 12,340 mL

7 0
3 years ago
Read 2 more answers
If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?
Lostsunrise [7]
Since \mathrm M_Y(t)=e^{6(e^t-1}, we know that Y follows a Poisson distribution with parameter \lambda=6.

Now assuming \mu,\sigma denote the mean and standard deviation of Y, respectively, then we know right away that \mu=6 and \sigma=\sqrt6.

So,

\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028
6 0
4 years ago
In a carnival​ game, the player selects a ball one at a​ time, without​ replacement, from an urn containing twotwo purplepurple
dezoksy [38]
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, t</span>he possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}

<span>1. Write down the probability distribution for the player earning

The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
</span>The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
The player earnings would be: 3*$1.5 -$4= $0.5
wwwp= (4*3*2*2)/(6*5*4*3*2)= 2/15 
The player earnings would be: 4*$1.5 -$4= $2
wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
The player earnings would be: 5*$1.5 -$4=  $3.5

2. Find its expected value

The expected value would be:
chance of event * earning 
You need to combine the 5 possible outcomes from the number 1 to get the total expected value.

Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)= 
(-12.5  -4 + 1.5 + 4 + 3.5) /15= -$7.5
This game basically a rip off.
6 0
3 years ago
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