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lapo4ka [179]
4 years ago
15

When 5 grams of wood burns completely in 15 grams of oxygen, 10 grams of water and some carbon dioxide are given off. A. Identif

y the reactants) in this reactions. B. How many grams of carbon dioxide would be produced in this example? C. What is the name of the law that you used to determine the answer for B?
Chemistry
1 answer:
antoniya [11.8K]4 years ago
5 0
Reactants- wood, oxygen
10 grams CO2
Law of Conservation of Mass
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How is stoichiometry used to calculate energy released when a mass of liquid freezes?
kati45 [8]

Answer:

D. Grams liquid x mol/g x delta Hf​reezing

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to reason that the stoichiometry used to calculate energy released when a mass of liquid freezes, involves the grams of the liquid, the molar mass of the liquid, as given in all the group choices, and the enthalpy of freezing because that is the process whereby a liquid goes solid.

In such a way, we infer that the correct factor would be D. Grams liquid x mol/g x delta Hf​reezing which sometimes is the negative of the enthalpy of fusion as they are contrary processes.

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6 0
3 years ago
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Matter is anything that has mass and takes up space. Which units of measurement can you use to describe these two properties?
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Answer:

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Explanation:

The SI unit for density is the kilogram per cubic meter (kg/m3 ).

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How many kilometers are there in 4.5 x 10^3 meters ?
Len [333]
1 meter = .001 kilometers so 4.5 x 10^3 = 4500 so .001 x 4500 = 4.5 kilo
7 0
4 years ago
Calculate the density of CO2 in g/cm3 at room temperature(25 degrees Celsuis) and pressure(1 atm) assuming it acts as an ideal g
Readme [11.4K]

Answer:

density=1.8x10^{-3}g/mL

Explanation:

Hello,

Considering the ideal equation of state:

PV=nRT

The moles are defined in terms of mass as follows:

n=\frac{m}{M}

Whereas M the gas' molar mass, thus:

PV=\frac{mRT}{M}

Now, since the density is defined as the quotient between the mass and the volume, we get:

P=\frac{m}{V} \frac{RT}{M}

Solving for m/V:

density= m/V=\frac{PM}{RT}

Thus, the result is given by:

density=\frac{(1atm)(44g/mol)}{[0.082atm*L/(mol*K)]*298.15K} \\density=1.8g/L=1.8x10^{-3}g/mL

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8 0
3 years ago
Which element has properties of both metals and nonmetals?
PilotLPTM [1.2K]
<span>Metalloids have the properties of metals and nonmetals.</span>
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3 years ago
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