Sodium mn2 and po4 makes sodium
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution
there are 1.00 mol in 1 L of solution
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L
volume of HCl required is 0.150 L
Answer:
1. Convert given mass of reactant to moles.
2. Convert moles of reactant to moles of product using the coefficients in the balanced equation.
3. Convert moles of product back to grams of product
Explanation:
In order to find out the mass of a given product in grams you would have to convert the grams into moles by multiplying 1 mole over the given mass of the reactant. Then, you would convert the moles of the reactant into moles of the product using mole ratio. And lastly, you would multiply by the mass of the product to calculate the mass back to grams.
Hope this helps!!<3
Given:
Volume of each of the solutions = 100 mL of each
Concentration of HCl = 0.10 M
Concentration of HNO3 = 0.10 M
Concentration of NaOH = 0.10 M
If all are mixed in one solution, the pH will surely be low since there are two acids mixed with one base. The pH range should be 1 - 5. <span />
Answer:
4.444... m/s
Explanation:
Because it increases by 40 m/s in 9 seconds so 40/9= 4.444... m/s
