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3 years ago

Ionic compounds blank

Chemistry

1 answer:

Sveta_85 [38]3 years ago

8 0

C, Have varying solubilities

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An ideal gas has a volume of 18.25 L at a temperature of 15.9 °C. The temperature of the gas is raised to 40.7 °C while the numb

Fynjy0 [20]

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V₂ = V₁ / T₁ * T₂ . If you prefer to set the final volume and want to estimate the resulting temperature, then the equation of Charles' law changes to: T2=T1/T1 multiplied by v^2.

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2 years ago

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A- Gases do not have mass.

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3 years ago

If you multiply an objects weight times it height, what value do you compute?

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3 years ago

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What other elements does iron commonly bonds with.

Neko [114]

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

it can bond with oxygen to form rust or iron oxide. and it can bond with carbon to form steel.

Here's another one: Iron bonds with lots of things: Oxygen (Ferric Oxide = rust),Chlorine (Ferric Chloride]), Fluorine, ... , even other Iron (in aMetallic Bond or crystal).

Hope it helps.

Have a nice day hyung/noona!~ ￣▽￣❤️

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3 years ago

How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac

Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

• using the molar mass of Ca(OH)2 (74g/mol).

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

• using the molar mass of HNO3 (63.02g/mol).

$4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3$

So, 7.32g of HNO3 are required.

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1 year ago