The given formula is f(x) = 20(1.2)^x
The formula is the starting amount multiplied by 1 + the percentage raised to the number of weeks.
A) the percent increase is 20% ( 1.2 in the formula is 1 +20% as a decimal)
B) the original amount is $20
C) for 2 weeks, replace x with 2 and solve:
20(1.2)^2
20(1.44) = $28.80
After 2 weeks the coupon is $28.80
D) To solve for the number of weeks (x) set the equation equal to $100:
100 = 20(1.2)^x
Divide both sides by 20:
5 = 1.2^x
Take the natural logarithm of both sides:
ln(5) = ln(1.2^x)
Use the logarithm rule to remove the exponent:
ln(5) = x ln(1.2)
Divide both sides by ln(1.2)
x = ln(5) / ln(1.2)
Divide:
X = 8.83
At 8.83 weeks the coupon would be $100, so after 9 weeks the coupon would be greater than $100
The answer is 9 weeks.
At least 4
10% of 12 is 1.2
So 30% is 3.6
And 1% 0.12
So 2% is 0.24
Plus 3.6 onto 0.24 and you get 3.84
4x+40-3x-2-x
(4x-3x-x)=4x-4x=0
(40-2)=38
The answer will be 38
Answer:
Step-by-step explanation:
They are equal. When the negative sign is inside the box the absolute value is positive, when the negative sign is outside the box THEN it is negative.
