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Anna35 [415]
3 years ago
9

How many ways can the letters in the word D-I-N-O-S-A-U-R be arranged?

Mathematics
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

40,320 ways

Step-by-step explanation:

To find the number of ways that the letters can be arranged, as all letters are different, we just need to find the factorial of the number of letters.

As we have 8 different letters, the number of ways is:

Factorial(8) = 8*7*6*5*4*3*2 = 40,320 ways

We can arrange the letters in 40,320 different ways.

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PLEASE HELP!!
artcher [175]

To solve for f, you need to isolate/get the variable by itself in the equation:

4(0.5f - 0.25) = 6 + f       Distribute 4 into (0.5f - 0.25)

(4)0.5f + (4)(-0.25) = 6 + f

2f - 1 = 6 + f        Subtract f on both sides to get "f" on one side of the equation

2f - f - 1 = 6 + f - f

f - 1 = 6       Add 1 on both sides to get "f" by itself

f - 1 + 1 = 6 + 1

f = 7

PROOF

4(0.5f - 0.25) = 6 + f      Substitute/plug in 7 into "f" since f = 7

4(0.5(7) - 0.25) = 6 + 7

4(3.5 - 0.25) = 13

4(3.25) = 13

13 = 13

8 0
3 years ago
What solid figure has 7 vertices?
Natalija [7]
Pyramids or prisms can have 7 or more vertices.
3 0
3 years ago
Help quick ❗️❗️ Which sequence of transformations will change did your PQRS to figure P’Q’R’S’?
babymother [125]

Answer:

Counterclockwise rotation about the origin by 90° followed by reflection over the Y-axis ⇒ answer (D)

Step-by-step explanation:

* Lets revise the reflection and the rotation of a point

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) rotated about the origin by angle 90° counter clockwise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clockwise

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise or  

anti-clockwise around the origin

- In our problem

# The vertices of the original figure are:

  P(1 , -3) , Q (3 , -2) , R (3 ,-3) , S (2 , -4)

# The vertices of the image are:

  P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

∵ x and y are switched

∴ The figure is rotated about origin by 90°

∵ The signs of the x-coordinates and the y-coordinates

   didn't change

∴ The rotation is followed by reflection, to know about which

   axis we must to find the images after the rotation

∵ P (1 , -3) ⇒ after rotation 90° counter clockwise is (3 , 1)

∵ Q (3 , -2) ⇒ after rotation 90° counter clockwise is (2 , 3)

∵ R (3 , -3) ⇒ after rotation 90° counter clockwise is (3 , 3)

∵ S (2 , -4) ⇒ after rotation 90° counter clockwise is (4 , 2)

* The images are P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

- The sign of x-coordinates of all of them changed

∴ The rotation followed by reflection over the y-axis

* The answer is ⇒ Counterclockwise rotation about the origin

  by 90° followed by reflection over the Y-axis

7 0
3 years ago
Identify the solution(s) of v2+11v−26=0.
miss Akunina [59]

Answer:

i solved for v and got

v = 2, -13

i hope this helps :]

4 0
3 years ago
At a chocolate store, 70% of the items are dark chocolate and 30% are milk chocolate. Also 20% of the items have nuts and 80% ar
Delvig [45]

Answer:

A. 13%

Step-by-step explanation:

let's suppose there's 1000 bars of chocolate in general

70 % dark = 700 dark choco bars

30 % milk = 300 milk choco bars

20 % have nuts = 200 bars have nuts

80 % don't have nuts = 800 bars don't have nuts

if 90 % of dark chocolate bars don't have nuts, that means 630 dark chocolate bars don't have nuts, but 70 have nuts

200 bars in general have nuts, if only 70 dark chocolate bars have nuts,

200 - 70 = 130

130 = 13%

7 0
3 years ago
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