PLEASE HELP ME !!!!!!!!!!!!!!!!

1 answer:

8 0

So in slope intercept form or y=mx+b or in your case c=mx+b where b=15, x=number of movies and b=2 dollars per cd then C=2x+15 so the C intercept is when x=0 so set x to 0 and get 2(0)+15=C 0+15=C C=15 Cintercept=15 slope=m so slope=2 C intercetp=15 so if borrow certain number of movies just plug in the values for x so 1 2(1)+15=2+15=17 2 2(2)+15=4+15=19 and so on

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Burka [1]

Answer:

6/x^5-2x-8

Step-by-step explanation:

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6/x-8-3x/x^-5

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Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .