Question

Simplify: Negative two and one-third minus negative ten and one-sixth

Answer 1

Answer:

$1.\rightarrow -2 \frac{1}{3}-(-10) \frac{1}{6}\\\\\rightarrow \frac{-7}{3} -\frac{-61}{6}\\\\\rightarrow \frac{-14+61}{6}\\\\\rightarrow \frac{47}{6}\\\\\rightarrow 7\frac{5}{6}$

Option C→Seven and five-sixths

2.

(-3) +(-5)

Mark -3 and -5 on the number line.Move 5 units left of -3 to reach at -8.That is required sum.

3.

Distance between −12 and −15 on the number line is given by

       |-12 -(-15}| or |-15 -(-12)|

=|-12+15| or |-15+12|

=|3| or |-3|

=3 units

Option C

|−12 − (−15)| = 3