What are the Factors of 32 and 72?

Mathematics

2 answers:

Sav [38]3 years ago

5 0

Answer:

The gcf of 32 and 72 can be obtained like this: The factors of 32 are 32, 16, 8, 4, 2, 1. The factors of 72 are 72, 36, 24, 18, 12, 9, 8, 6, 4, 3, 2, 1. The common factors of 32 and 72 are 8, 4, 2, 1,

Step-by-step explanation:

Alexus [3.1K]3 years ago

4 0

Answer:

The factors of 32 are 32, 16, 8, 4, 2, 1. The factors of 72 are 72, 36, 24, 18, 12, 9, 8, 6, 4, 3, 2, 1. The common factors of 32 and 72 are 8, 4, 2, 1, intersecting the two sets above.

plz mark brainliest :DD

You might be interested in

DON’T SEND A LINK! WHAT IS THE SLOPE OF THIS LINE THE SLOPE IS NOT 4/1 OR 20/5

aleksandrvk [35]

Answer:

25/5

Step-by-step explanation:

i think

7 0

2 years ago

Read 2 more answers

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$