Answer:
The differential equation is ![\frac{dx(t)}{dt} = k x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%3D%20k%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
Step-by-step explanation:
From the question we are told that
The number of students are 
The number of student that have contracted the flu is x(t)
The number of student that don't have the flu is mathematically represented as
The rate at which the disease spread is proportional to the number of interactions between students with the flu and students who have not yet contracted it, which can be mathematically represented as
![\frac{dx(t)}{dt} \ \ \ \alpha\ \ \ x(t) [7000 - x(t)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%28t%29%7D%7Bdt%7D%20%5C%20%5C%20%5C%20%5Calpha%5C%20%5C%20%5C%20%20%20x%28t%29%20%5B7000%20-%20x%28t%29%5D)
=>
What do you need help with
Equation for this problem: Total 3 cubed / (L x W)
So 18.5cm x 15cm = 277.5 is the product of L and W. Now you need to devide the total by 277.5 which is 14. So the aquarium is 14 cm deep.
Answer:
use app Gauthmath its will give you the answer
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
