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3 years ago

(-1, -30) a solution of y = 10x? a) True b) False

Mathematics

2 answers:

loris [4]3 years ago

7 0

the answer is false hoped this helps

Travka [436]3 years ago

5 0

~Psst, hey kid~

I believe the answer is false, because y = 10x means the x, (1) is being multiplied by 10, also it's a negative, and 10x is a positive equation.

Hope this helped...

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Masteriza [31]

The answer is 121,434,796.00165

7 0

3 years ago

Please help (CORRECT ANSWERS ONLY)

german

-2(8m+8) = -16

-16m - 16 = -16

His first mistake lies in his distribution. When multiplying -2 * 8, he made it a positive 16, when he should have made it a negative 16.

-16m - 16 = -16

Add 16 to each side.

-16m = 0

Divide that by -16

m = 0

7 0

3 years ago

A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o

Komok [63]

Answer: Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$ , where $\overline{x}$ = sample mean, n= sample size, s= sample standard deviation, $t_{\alpha/2}$ = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

$\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05$

Critical t-value : $t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622$

So, the 95 percent confidence interval estimate for the mean :

$242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)$

The 95 percent confidence interval estimate for the mean:(190.14, 295.06)

8 0

3 years ago

Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle is in the triangle. HELP PLE

sashaice [31]

Answer:

$0.02$

Step-by-step explanation:

we know that

The probability that a point chosen randomly inside the rectangle is in the triangle is equal to divide the area of the triangle by the area of rectangle

Let

x-----> the area of triangle

y----> the area of rectangle

P -----> the probability

$P=x/y$