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poizon [28]
3 years ago
15

For a scale to pass inspection, the scale's reading can vary by at most

Mathematics
2 answers:
bezimeni [28]3 years ago
5 0

Answer:

2.5 grams I think or 0.25

Step-by-step explanation:

worty [1.4K]3 years ago
5 0

Answer:

I think its 249.99 to 250.01

Step-by-step explanation:

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Find the zeroes of the following equation:
weqwewe [10]

Answer:  \bold{x=\dfrac{1\pm \sqrt5}{2}}

                both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}

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3 years ago
PLZ HELP I REALLY NEED IT
Ber [7]

Answer:

18 Inches

Step-by-step explanation:

1 foot + 12 in + 6 in = 18 in

6 0
3 years ago
Jenna worked at an ice cream cart for 8.75 hours on Friday, 7.5 hours on Saturday she made a total of 178.25 How much does Jenna
Musya8 [376]
Jenna gets paid a total of 10.97 cents an hour<span />
4 0
4 years ago
Read 2 more answers
Please help me understand.
USPshnik [31]

Answer:

B) 2

Below I wrote the steps on how I would find the answer.

Step-by-step explanation:

1. Yep, so basically cba = cbl + lba.

2. So you need to find x

3. So basically if you set up the equation 61x - 2 = 13x - 1 + 95

4. Then you can solve for x

5. X = 2

5 0
1 year ago
Derivatives of inverse trigonometric functions please explain answers
Jobisdone [24]

I'll explain how to do the first one:-

y = cos-1(x2)

This can be described as ' a function of a function'   x^2 is a function of x and cos-1(x^2) is a function of x^2.

We need to  apply the chain rule.

Personally I find this  easier to understand if i let u = x^2, so

If y = f(u) and u is a function of x then

dy/dx = dy/ du * du/dx

Here u = x^2  and y = cos-1(u)

du/dx = 2x

so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx


= -1 / √(1 - u^2) * 2x

= -2x / √(1 - u^2)    

= -2x / √(1 - (x^2)^2)

= -2x / √(1 - x^4)

I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.

6 0
3 years ago
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