Answer:
W and X
Step-by-step explanation:
These are the ones with symmetry
Answer: Option 4
Step-by-step explanation:
Similar triangles have congruent angles, so this means that the sines, cosines, and tangents should be the same.
Thus, the side lengths of the triangle we want to find should be multiples of
.
- This eliminates options (1) and (3).
Between options 2 and 4, we know that the Pythagorean theorem is not satisfied by option (2), thus we should eliminate it.
This leaves us with option (4)
Answer: the measure of angle 1 is 55 degrees
Step-by-step explanation:
so you see the outside of 5 is 125 degrees on the right side? So that 125 is equal to the 5 on the other side. So to find measure 1 you need to figure out the measure of the rest of the outside which is the outer angle of measure 1.
So you do
125+125=250
and then,
360-250=110
and since measure of angle 1 starts at the edge of the angle and not the center, you do 110/2 which is 55.
IF THE ANGLE OF MEASURE 1 WAS FROM THE CENTER POINT TO THE END <u>DO NOT </u>DIVIDE BY TWO.
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
This is the answer
if u do 3rd, 4th .... derivatives the answer will be 0 again.