Start by writing the system down, I will use
to represent 

Substitute the fact that
into the first equation to get,

Simplify into a quadratic form (
),

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

which then must factor into

And the solutions will be
.
Clearly for small coefficients like ours
, this is very easy to figure out. To get 5 and 6 we simply say that
.
This fits the definition as
and
.
So as mentioned, solutions will equal to
but these are just x-values in the solution pairs of a form
.
To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.
So the solution pairs are
and
.
Hope this helps :)
Prime only has two factors one and its self a composite number has more factor than one and its self
exsample: 12 - 1,2,3,4,6,12 = 12 is a composite number
7 - 1,7 =prime number
b r = 178 + h;
b r + h = 676;
then, 178 + 2h = 676 => h = 498/2 = 249 => b r = 178 + 249 = 427
Answer:
676
Step-by-step explanation:
h=b+178=427
b=b=249
-------------
(b+178)+b=676
2b+178=676
2b=498
b=249
-------------
249+427=676
Kaneppeleqw and 2 more u
Answer:
5.848 in
Step-by-step explanation:
Divide the piece of cardboard into nine equal squares of side z.
The centre square is the base of the cube.
When you cut out the corner squares and fold up the sides, you will have a cube with edge length z.
The cube must have a volume of 200 in³.
V = z³
200 = z³
![z = \sqrt[3]{200}](https://tex.z-dn.net/?f=z%20%3D%20%5Csqrt%5B3%5D%7B200%7D)
![z = \sqrt[3]{8\times25}](https://tex.z-dn.net/?f=z%20%3D%20%5Csqrt%5B3%5D%7B8%5Ctimes25%7D)
![z = 2\sqrt[3]{25}](https://tex.z-dn.net/?f=z%20%3D%202%5Csqrt%5B3%5D%7B25%7D)
z = 2 × 2.924
z = 5.848 in
The edge length of the cube is 5.848 in.