Help me graph<br><br> y=3-|x-1|

It shows the equations but it is a little confusing I don't want to get the problem wrong please help me out. Ill give you brain

Viktor [21]

Answer:εδΑΒΓΒΕ

$U4\leq \sqrt{x} \sqrt[n]{x} 64$

Step-by-step explanation:

73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±

6 0

2 years ago

27. Use Structure Use the table at the right. Yolanda is planning a party that will take place in three rooms. a. Write an expre

BabaBlast [244]

Answer:

25t+95 or 5(5t + 19)

Step-by-step explanation:

The total of the sound fee = $25

The total of the rental fee = $95

Write is as an equation and you can get 25t + 95 or 5(5t + 19)

5 0

3 years ago

What is the zeros of the quadratic function y=x^2+14x+24

777dan777 [17]

Step-by-step explanation:

${x}^{2} + 14x + 24 = 0 \\ {x}^{2} + 12x + 2x + 24 = 0 \\ x(x + 12) + 2(x + 12) = 0 \\ (x + 12)(x + 2) = 0\\ x = - 12 \\ x = - 2$

6 0

3 years ago

Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC

Marysya12 [62]

BC is 10 units and AC is $5+5\sqrt{3}$ units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}$
AB is opposite to ∠C
BC is opposite to ∠A
AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ $\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

∵ AB = $5\sqrt{2}$

- Substitute AB and the 3 angles in the rule above

∴ $\frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}$

- By using cross multiplication

∴ (BC) × sin(30) = $5\sqrt{2}$ × sin(45)

∵ sin(30) = 0.5 and sin(45) = $\frac{1}{\sqrt{2}}$

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ $\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

- Substitute AB and the 3 angles in the rule above

∴ $\frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}$

- By using cross multiplication

∴ (AC) × sin(30) = $5\sqrt{2}$ × sin(105)

∵ sin(105) = $\frac{\sqrt{6}+\sqrt{2}}{4}$

∴ 0.5 (AC) = $\frac{5+5\sqrt{3}}{2}$

- Divide both sides by 0.5

∴ AC = $5+5\sqrt{3}$ units

BC is 10 units and AC is $5+5\sqrt{3}$ units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0

3 years ago

Help me asap (please please)

CaHeK987 [17]

Area of a circle = pi*r^2.

Here, A = 380.13 mi. Unfortunately, "mi" is NOT a unit of area.

So I will assume that the problem should read A = 380.13 sq. miles.
380.12 mi^2
Thus, 380.13 mi^2 = 3.14*r^2, and r^2 = ------------------- 121.057 mi^2
3.14

The radius is the sqrt of 121.057 mi^2: 11.00 miles.

The diam. is twice that, or d = 22.00 miles.

4 0

3 years ago

Help me graph y=3-|x-1|