The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
After
using a calculator to find sin 21 degrees and rounding it to four decimal places,
I got 0.3584. The correct answer between all the
choices given is the first choice. I am hoping that this answer has satisfied
your query and it will be able to help you in your endeavor, and if you would
like, feel free to ask another question.
Answer:
9
Step-by-step explanation:
y-11=25-3y
y + 3y = 25 + 11
4y = 36
y = 36 / 4
y = 9
Hope it will help :)
Answer:
3/6
Step-by-step explanation:
there are 6 sides: 3 odd and 3 even numbers
if you need to find the probability of rolling an odd number, take the number of odd possibilities and form a fraction with the number of total sides, 6.
so, 3/6 Or 1/2
