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zheka24 [161]
3 years ago
13

X^2 - 9x -10 =0 has a discriminant of: a. 121 b. 72 c. -359 d. 41 e. 136

Mathematics
1 answer:
Feliz [49]3 years ago
7 0
In the standard form of quadratic
ax^{2} +bx+c
the discriminant is
b^{2} -4ac
In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.
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Ramona went out with her 3 sisters, they spent $58 plus
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<h2>Problem:</h2>

Ramona went out with her 3 sisters, they spent $58 plus 9% tax on their meal. They also left 15% tip. If they divided up the bill evenly, how much did each of them spend?

<h2>Solution:</h2>

\frac{58 + 58(9\% + 15\%)}{3}

=  \frac{58 + 58(0.09 + 0.15)}{3}

=  \frac{58 + 58 \times 0.24}{3}

=  \frac{58 + 13.92}{3}

=  \frac{71.92}{3}

= 23.97

<h2>Answer:</h2>

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8 0
3 years ago
A football team loses 3 yards, gains 12 yards, gains 10 yards, and then loses 15 yards. Did the team gain yards or lose yards ov
e-lub [12.9K]

Answer: the answer is 4

Step-by-step explanation:

5 0
2 years ago
Find the missing side lengths. Leave your answers in simplest radical form.
saveliy_v [14]
ANSWER:
d. x = 15, y= 15√3

EXPLANATION:
This is a special triangle, more specifically a 30-60-90 degree triangle. For sake of not confusing x and y, we will use z to use as our reference for solving this triangle. The side lengths for each angle are as follows:
• 60 degrees = z√3
- this is the value for your y answer
• 30 degrees = z
- this is the value for your x answer
• Hypotenuse = 2z
- this is what we already have

We solve for what we already have which is the Hypotenuse = 30:
2x = 30
x = 15

We now have our x value which is 15.
Now we just plug in that x value for every expression for every angle.

x = 15
y = 15√3

Sorry if I explained it too thoroughly but I’ll be glad to answer any questions or clarifications



8 0
2 years ago
Please answer this question! 20 points and brainliest!
azamat

Step-by-step explanation:

You have to substitute... 0, 5, & 10, & 3

y = 2x + 3

y = 2(0) + 3

y = 0 + 3

y = 3

(0,3)

y = 2x + 3

y = 2(5) + 3

y = 10 + 3

y = 13

(5,13)

y = 2x + 3

y = 2(10) + 3

y = 20 + 3

y = 23

(10,23)

y = 2x + 3

y = 2(3) + 3

y = 6 + 3

y = 9

(3,9)





5 0
2 years ago
Find the remainder when x4 - 5x3 + x2 - 10x - 5 is divided by x + 3.
m_a_m_a [10]

Use the remainder theorem: we can decompose the given polynomial in terms of quotient and remainder polynomials q(x) and r(x), respectively, such that

x^4 - 5x^3 + x^2 - 10x - 5 = (x + 3) q(x) + r(x)

Then letting x = -3 makes the quotient term vanish, and we're left with a remainder of

r(-3) = (-3)^4 - 5\times(-3)^4 + (-3)^2 - 10\times(-3) - 5 = \boxed{250}

3 0
2 years ago
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