Geometry Help

Archy [21]

Answer:

Step-by-step explanation:

6 0

3 years ago

Translate the sentence into an inequality. Twice the difference of a number and 8 is at least 26 . Use the variable w for the un

Olin [163]

"At least" refers to greater than or equal to (≥).
This is because "at least" means:
- it can't be less than
- it can be equal to
- it can be greater than
This is basically like saying no less than.
If you must have at least 10 oranges for some recipe, then you must have 10 oranges, but you can also have more.

"Twice the difference of a number and 8"
This means that 2 times a number minus 8.
This can be written as 2(w - 8), since w is unknown and it's the difference between w and 8.
The 2 is being multiplied by this because it's 2 times this difference.

"At least 26"
This means ≥ 26.

Now for the actual inequality.
"Twice the difference of a number and 8"
translates to 2(w - 8)
"is at least 26"
translates to ≥ 26
Now put them together.
2(w - 8) ≥ 26

So the answer is 2(w - 8) ≥ 26.

Hope this helps! :)

7 0

3 years ago

Q#7: Solve for the variable: 3(x+2) - 9 = 15 - 4(5x - 2) Make sure you round you answer to the nearest whole number.

masya89 [10]

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$\blue\textsf{\textbf{\underline{\underline{Question:-}}}}$

3(x+2)-9=15-4(5x-2)

$\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}$

First use the distributive property of both sides:-

3(x+2)-9=15-4(5x-2)

3x+6-9=15-20x+8

Now add 20x on both sides:-

23x+6-9=15+8

On simplification,

23x-3=23

Add 3 to both sides:-

23x=26

Divide by 23 on both sides:-

x=26/23

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3 0

2 years ago

Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.

IRISSAK [1]

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner: -(2-3i)(x)=-x(2-3i)

Last: (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9 (since i^2=-1)

x^2-4x+13 (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

x^2+1

---------------------------------------

x^2-4x+13| x^4-4x^3+14x^2-4x+13

-( x^4-4x^3+ 13x^2)

------------------------------------------

x^2-4x+13

-(x^2-4x+13)

-----------------

0

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

$x^2+1=0$

$x^2=-1$

$x=\pm \sqrt{-1}$

$x=\pm i$

So the zeros are i, -i , 2-3i , 2+3i

7 0

4 years ago

Sandy is selling her jewelry at a craft show. She has already sold 50 necklaces and sells 4 per hour (h). Write an equation that

ki77a [65]

Answer:

4 divided by 50

Step-by-step explanation:

3 0

3 years ago