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VARVARA [1.3K]
3 years ago
6

Which is the most appropriate operation to use to solve this problem? - Tony's job is to stack the cans on the shelves at the lo

cal store. He has 585 cans to stack evenly on 15 shelves. How many cans should he place on each shelf? *
A) multiplication
B) division
C) subtraction
D) addition
Mathematics
2 answers:
maria [59]3 years ago
4 0
I would say division
seropon [69]3 years ago
3 0
I would say division, you are trying to see how many cans can fit on those 15 shelves so you should do 585/15.
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I need help with this pleaseeee!!
anastassius [24]

Answer:

A

Step-by-step explanation:

I guessed

5 0
2 years ago
Please help ASAP!!!!!!!!!!!
Effectus [21]

Answer:

x = 3.76 ft

Step-by-step explanation:

To find the missing side, "x", solve using proportions.

In similar polygons, the 'new' polygon was created by multiplying every side of the 'old' polygon by the same number. Every side was multiply by the <u>scale factor</u>, "k", which tells you how much a polygon grew (k>1) or shrunk (0<k<1).

Therefore, if you divided the pairs of corresponding sides, they would be equal.

From the diagram, you can tell that the following sides correspond:

CB ~ GF

AB ~ EF

<u>Use the proportion</u>

\frac{EF}{AB} = \frac{GF}{CB}

\frac{x}{6ft} = \frac{3.3ft}{5ft}      Substitute values from diagram

6ft*\frac{x}{6ft} = 6ft*\frac{3.3ft}{5ft}       Multiply both sides by 6 ft

x = \frac{6ft*3.3ft}{5ft}        "x" is isolated. Multiply fraction by combining into numerator

x = \frac{19.8ft}{5ft}        Solved numerator. Divide for decimal answer.

x = 3.76ft

The value of 'x' is 3.76 ft.

4 0
2 years ago
Whoever gets this correct gets brainliest
AlekseyPX

Answer:

More. Older

Likey

To vote

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vote

8 0
3 years ago
Find m&lt;q plzzzzzzzzzzz
Eva8 [605]
66 is the answer
 76+ 38= 114
114+ 66 = 180
4 0
2 years ago
Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f
sergeinik [125]
f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\&#10;\hbox{statement 1 is false} \\ \\&#10;f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\&#10;f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8&#10;\\ f(-2)=f(2) \\&#10;\hbox{statement 2 is true}

f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\&#10;f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\&#10;71+8 \not= 143 \\&#10;f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\&#10;f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\&#10;71 \times 8 \not= 296 \\&#10;f(5) \times f(2) \not= f(10) \\&#10;\hbox{statement 4 is false}

Stamement 2. f(-2)=f(2) is true.
3 0
3 years ago
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