Check the forward differences of the sequence.
If
, then let
be the sequence of first-order differences of
. That is, for n ≥ 1,

so that
.
Let
be the sequence of differences of
,

and we see that this is a constant sequence,
. In other words,
is an arithmetic sequence with common difference between terms of 2. That is,

and we can solve for
in terms of
:



and so on down to

We solve for
in the same way.

Then



and so on down to


Answer:
Options a, d and e
Step-by-step explanation:
We check the validity of each of the options.
Kindly note that we can express the equation fully and we have;
y-3 = -2x-10
y = -2x -10 + 3
y = -2x -7
So let’s now evaluate the options.
(a) Insert the value of x at this point, if it gives the value of y, then it’s on the line
the value of x to insert is -5 here.
Thus ; y = -2(-5)-7 = 10-7 = 3
since y is 3, then it is on the line
(b) same as a
insert x = 5
y = -2x-7
y = -2(5) -7
y = -10-7 = -17
This is definitely not on the line as the value of y gotten does not correlate with what was given
c. To get this , compare with the standard form of
y = mx + c
where m is slope
Here our m is -2 , so this is definitely wrong
d) From above , we can see that this is correct
e) compare this with y = mx + c
c is our intercept and this is equal to -7 which makes this option also correct
B. P+Q
This the answer on edmentum
Answer:
7x+39>=53 and 16x+ 15>31 x>=2 (no solutions exist)
Step-by-step explanation: