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olasank [31]
3 years ago
5

Find the equation of the line through ( - 10, - 8) that is perpendicular to the line through (10,6), (5,5).

Mathematics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

y=-5x-58

Step-by-step explanation:

The equation of a line in slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

Perpendicular lines have opposite reciprocal slopes.

Anyways we need to find the slope of the line going through (10,6) and (5,5).

To find the slope, we are going to line up the points vertically and subtract vertically, then put 2nd difference over 1st difference. Like so:

 (  10   ,   6)

- (   5   ,   5)

------------------

    5         1

So the slope of the line through (10,6) and (5,5) is 1/5.

The slope of a line that is perpendicular will be the opposite reciprocal of 1/5.

The opposite reciprocal of 1/5 is -5.

The line we are looking for is y=-5x+b where we need to find the y-intercept b.

y=-5x+b goes through (-10,-8)

So we can use (x,y)=(-10,-8) to find b in y=-5x+b.

y=-5x+b with (x,y)=(-10,-8)

-8=-5(-10)+b

-8=50+b

Subtract 50 on both sides:

-8-50=b

-58=b

So the equation is y=-5x-58

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(-4x^5)^2(-2x^4)^5<br> Please help????!
ycow [4]

Answer:

-512x^{30}

Step-by-step explanation:

(-4x^5)^2 = 16x^{10}\\(-2x^4)^5 = -32x^{20}\\16x^{10} * -32x^{20} = -512x^{30}

8 0
3 years ago
determine m contains the points with coordinates (-4,1) and (5,8) and line n contains the points with coordinates (6,-2) and (10
Dafna11 [192]
I drew up a (bad looking but still useful) grid and it proves the answer to be neither. even if the lines went continued in each direction it shouldn't be possible 

4 0
3 years ago
Which function in Excel is used to perform a test of independence? a. T.TEST b. CHISQ.TEST c. NORM.S.DIST d. Z.TEST
denis23 [38]

Answer:

b. CHISQ.TEST

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

The statistic is given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}

In order to calculate the p value we need to have in count the degrees of freedom , on this case df=(rows-1)(#cols-1). And we can calculate the p value would be given by:

p_v =P(\chi^2 >\chi^2_{calc})

But the correct comand is given by:

b. CHISQ.TEST(Actual range, Expected range)

We just need to put in one column the Observed values and in other the expectec values.

3 0
3 years ago
A representative of a car manufacturer in the United States made the following claim in a news report. "Ten years ago, only 53 p
Harman [31]

According to the p-value, the correct option regarding the decision of the test hypothesis is:

v. No, because 0.283 > 0.05.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if the proportion is still of 0.53, that is:

H_0: p = 0.53

At the alternative hypothesis, we test if it has increased, that is:

H_1: p > 0.53.

<h3>What is the decision according to the p-value?</h3>

  • If p-value > significance level, we do not reject the null hypothesis.
  • If p-value < significance level, we reject the null hypothesis.

In this problem, the p-value is of 0.283 > 0.05, hence there is not sufficient evidence to conclude, at the significance level of a = 0.05, that the proportion of all car owners in the United States who own American-made cars has increased from what it was ten years ago, which means that option V is correct.

More can be learned about p-values at brainly.com/question/16313918

3 0
2 years ago
What is the value of x to the power of 6 + y to the power of 2 when x=1 and y=11
siniylev [52]

Answer: 122

Step-by-step explanation: Substitute the values of <em>x</em> and <em>y</em> into the expression.

x^6+y^2 \\ \text{ is like } \\ ( )^6 + ( )^2

"Fill in the blanks" with the numbers given for <em>x</em> and <em>y</em>.

(1)^6+(11)^2 = 1+121=122

4 0
3 years ago
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