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3 years ago

Help me for number 14 & 15

Mathematics

1 answer:

Hoochie [10]3 years ago

7 0

#15 50y+10 is the answer

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4. Write as a fraction in simplest form: 38 minutes to 12 minutes

yanalaym [24]

Answer:

3 ⅙

Step-by-step explanation:

38 and 12’s common factor would be 2. Now the fraction is 19/6.

How many 6’s can fit into 19? 3. With a remainder of 1 we have:

3 ⅙

6 0

3 years ago

Given the function f(x) = -5x + 11 + 3, for what values of x is f(x) = -12?<br> Bleaseeeeee

Nitella [24]

Answer:

x = 5.2

Step-by-step explanation:

$f(x) = -5x + 11 + 3$

Let's first simplify our first function:

$f(x) = -5x + 11 + 3\\f(x) = -5x + 14$

Now, we just need to set this function equal to our other given function.

$f(x) = -5x+14\\f(x) = -12\\-5x + 14 = -12$

Now, we can add 12 to both sides:

$-5x + 14 + 12 = -12 + 12\\-5x + 26 = 0$

Now, add 5x to both sides:

$-5x+26 = 0\\26 = 5x\\$

Finally, we'll divide both sides by 5:

$26/5 = 5x / 5\\5.2 = x\\x = 5.2$

Answer: x = 5.2

6 0

3 years ago

Read 2 more answers

Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)

Liono4ka [1.6K]

Answer:

The answer is "0".

Step-by-step explanation:

Please find the correct question in the attached file.

Given value:

$\to f(x) =\frac{x^2}{x^2+5}\\\\$

Formula:

$\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}$

$\to f'(x) =\frac{(x^2+5) 2x -2x^3 (2x)}{(x^2+5)^2}\\\\\to f'(0) =\frac{(0^2+5)2(0) -4(0)^4}{(0^2+5)^2}\\\\\to f'(0) =\frac{(0)(5) -2(0)}{(5)^2}\\\\\to f'(0) =\frac{0 - 0}{(5)^2}\\\\\to f'(0) =\frac{0}{25}\\\\\to f'(0) = 0$

6 0

3 years ago

Need help with this asap

valentina_108 [34]

Answer: the first one is exponential and the second one is function

6 0

3 years ago

100!!! Points

docker41 [41]

See the line is parallel to x axis.
The equation of that top is y<5

The range is

(-oo,0)U(oo,5)

-oo<y<5

Option D is correct

3 0

3 years ago