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Brilliant_brown [7]
3 years ago
15

Help me for number 14 & 15

Mathematics
1 answer:
Hoochie [10]3 years ago
7 0
#15 50y+10 is the answer
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The invention of the telegraph ______________ a. let distant locations communicate quickly. b. kept distant locations from commu
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The answer is a.......
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Find the cosine of ∠J.
RUDIKE [14]

Answer:

\cos =  \frac{base}{hypotenuse}  =   \\ \cos(j)  =  \frac{ \sqrt{29} }{ \sqrt{94} }    =   \sqrt{ \frac{29}{94} }  \\ answer =  \sqrt{ \frac{29}{94} }

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What is the value of the expression? −1/4+3/8 5/8 Enter your answer in simplest form.
galina1969 [7]
Decimal form
-0.015625

Exact form
-1/60
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7 0
3 years ago
What is the product of all possible digits x such that the six-digit number 341,4x7 is divisible by 3?
ss7ja [257]

Answer:

Step-by-step explanation:

x=2 and x = 5 and x = 8

341,427 mod 3 = 0

341457 mod 3 = 0

341487 mod 3 = 0

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4 0
3 years ago
A random sample of 200 shoppers at a local grocery store found that 135 of the 200 sampled
VMariaS [17]

Using the z-distribution, as we are working with a proportion, it is found that samples of 937 should be taken.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

  • The estimate is of \pi = 0.675.
  • The margin of error is of M = 0.03.
  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

Then, we solve for n to find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.675(0.325)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.675(0.325)}

\sqrt{n} = \frac{1.96\sqrt{0.675(0.325)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.675(0.325)}}{0.03}\right)^2

n = 936.4

Rounding up, it is found that samples of 937 should be taken.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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