y = mx + b slope(m) = 7/10 (8,5)..x = 8 and y = 5 now we sub and find b, the y int 5 = 7/10(8) + b 5 = 56/10 + b 5 - 56/10 = b 50/10 - 56/10 = b -3/5 = b
equation is : y = 7/10x - 3/5...but we need it in standard form
y = 7/10x - 3/5 -7/10x + y = -3/5 7x - 10y = 6
no, 7x - 10y = 3 is not a good model....because neither of ur points, when subbed in, will make this equation true