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3 years ago

A geologist visits 40 volcanoes in Alaska and California. 15% of the volcanoes are in California.

Mathematics

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

<h2>Most explained:</h2>

40% = 100%

15 = (100% - 15% = 85%) 85% in Alaska

California = 15% of 40 = (0.15 x 40) = 6

Alaska = 85% of 40 = (0.85 x 40) = 34

<h2>The simple way (or the way i found it simple):</h2>

<h3>(I found the simple way after i solve the first way)</h3>

Bye, i hope this helps.

<h3 />

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Round 573.073 to the greatest place

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Answer:

574

Step-by-step explanation:

To round a two-digit number to the nearest ten, simply increase it or decrease it to the nearest number that ends in 0: When a number ends in 1, 2, 3, or 4, bring it down; in other words, keep the tens digit the same and turn the ones digit into a 0

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3 years ago

What is the quotient of the division below?<br> 3387-<br> 45<br> 46<br> 48<br> 49

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Answer:

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Step-by-step explanation:

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3 years ago

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How to solve inter quartile range of the given data set? 3,9,12,15,16,18,21

s2008m [1.1K]

Answer:

Step-by-step explanation:

3,9,12,(15),16,18,21

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3 years ago

Question 12 down at the bottom of the file PDF<br><br> Im confuse on question 12

mezya [45]

Nothing shows up.. could you type it out?

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3 years ago

About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number

olganol [36]

Answer:

1) $E(X) = np = 120*0.1 =12$

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

2) $P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

$X\sim Binom(n= 120 , p =0.1)$

Part 1

The mean is given by:

$E(X) = np = 120*0.1 =12$

And the deviation would be:

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

$P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

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3 years ago