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Murrr4er [49]
3 years ago
13

How how do you solve this please explain​

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer:

1. have se x

Step-by-step explanation:

Lelu [443]3 years ago
7 0

Answer:

x = 36

Step-by-step explanation:

(3x + 10) + 62 = 180

3x = 180 - 62 - 10 = 108

x = 36

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Please help.......!!!!!!!!!!
Studentka2010 [4]

Answer:

20 feef

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Miriam took a taxi from her home to school. The taxi driver charged an initial fee of $4.50 plus $2 per mile. The total fare was
jekas [21]

Answer:

8 miles

Step-by-step explanation:

$20.50-$4.50= $16

$16/$2= 8 miles

Hope this helped! :)

7 0
3 years ago
It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
3 years ago
In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de
Naily [24]

Answer:

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation  

X_{1}=507 represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

n_{1}=32601 sample elected from arizona

\hat p_{1}=\frac{507}{32601} =0.0156 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

p_{2}=\frac{1}{88}= 0.0114 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD)  in the nation

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{507+1}{32601 +88}=0.01554  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

Statistical decision

The significance level provided is \alpha=0.01, and we can calculate the p value for this test.    

Since is a one right sided test the p value would be:  

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

5 0
3 years ago
A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. A single fisherman is
monitta
It is D, as 2 plus 3 is 5 which is half of 10.
4 0
4 years ago
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