4(-3)^2-5(-13)
-7^2+15
-7^17
Let C be the amount of compost
T be the amount of topsoil
Each compost cost = $25
Cost of C compost = 25C
Each topsoil cost = $15
Cost of T topsoil = 15T
Amount of compost + amount of topsoil = 10
C + T = 10 -------> Equation 1
cost of C compost + cost of T topsoil = 180
25C + 15T = 180 --------> equation 2
Solve the first equation for C
C + T = 10
C = 10 - T
Now plug it in second equation
25C + 15T = 180
25 ( 10 - T) +15T = 180
250 - 25T + 15T = 180 (combine like terms)
250 - 10 T = 180 (Subtract 250 on both sides)
-10T = 180 - 250
-10T = -70 ( divide by -10 on both sides)
T = 7
She purchased 7 cubic yards of topsoil .
2 is to 4 because 64/8 is 8. 4/2 is 2. 2 x 2 is in proportion to 8 x 8
The intersection of the two sets is the list of members that appear in both sets. That is {3}.
Your statement is FALSE.
let the number of adult tickets be x and the number of children tickets be y
3x + y = 164...equ(1)
2x + 3y = 174....equ(2)
multiplying equation 1 by 3
9x + 3y = 492
subtracting equation 2 from 1
7x = 318
x = 45.43 dollars
substituting the value of x into the equation
3(45.428) + y = 164
y = 164 - 3(45.428)
∴y = 27.71 dollars
