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3 years ago

Find the length and widgh of a rectangle with an area of 2x squared + x -3

1 answer:

7 0

This is an example

Your length of the rectangle is 2 times the width.
Let length = 2x
Let width = x
Now your area = 450m^2
2x.x = 450 ("." means multiply)
2x^2 = 450
Therefore x^2 = 225
Therefore x= 15
If your x=15 , then you know your width.
Length = 2x (2 x 15 = 30)
Therefore:
Length = 30m
Width = 15m
Hope that helped! :)

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Step-by-step explanation:

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AVprozaik [17]

Answer:

$X \sim N(61,14)$

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Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

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So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

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3 years ago