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3 years ago

14

$10,788 per dozen, find for EACH computer (a) dollar markup, (b) percent markup on cost, and (c) percent markup on selling price

, to the nearest hundredth percent

1 answer:

swat323 years ago

5 0

It’s A dollar markup

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I think it’s six because 3n=6-5 3 n=6-5 then subtract 5 5 from 6 6

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3 years ago

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Alinara [238K]

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3 years ago

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Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

alina1380 [7]

Answer:

The answer is $x=a^{-1}cb^{-1}$ .

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element $g\in G$ there exist another element, denoted by $g^{-1}$ such that $gg^{-1}=e$ , where $e$ stands for the identity element of G.

So, given the equality $axb=c$ we make a left multiplication by $a^{-1}$ and we obtain:

$a^{-1}axb =a^{-1}c.$

But, $a^{-1}axb = exb = xb$ . Hence, $xb = a^{-1}c$ .

Now, in the equality $xb = a^{-1}c$ we make a right multiplication by $b^{-1}$ , and we obtain

$xbb^{-1} = a^{-1}cb^{-1}$ .

Recall that $bb^{-1}=e$ and $xe=x$ . Therefore,

$x=a^{-1}cb^{-1}$ .

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3 years ago

Sofia is learning to knit. After her first three stitches, she had to undo the last two. Then she made three more stitches and a

Marizza181 [45]

She’ll have to make 4 more stitches in order to get 6 good ones. Each time she creates 3 she undoes 2 which after 4 more times would leave her with 6 good stitches.

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3 years ago

What is the rate of change between (29,9) and (33,10)?

Tema [17]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

The rate of change is a measure of the slope

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (29, 9) and (x₂, y₂ ) = (33, 10)

m = $\frac{10-9}{33-29}$ = $\frac{1}{4}$ ← rate of change

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3 years ago