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Burka [1]
3 years ago
5

A square piece of paper 10 cm on a side is rolled to form the lateral surface area of a cylinder and then a top and bottom are a

dded.
What is the surface area of the cylinder? (Write in terms of pi using symbol)
Mathematics
1 answer:
Anika [276]3 years ago
6 0

Answer:

The surface = pi*10cm2

Step-by-step explanation:

The area of any rectangle is Base *  Height,

We know that the square originally has 10cm High, when is rolled to form a cylinder, it's new shape has a bottom side that is equals to a circle.

The length of a circle is 2*pi*Radio= pi*Diameter.

Since the square has the same length in each side, we know that pi*Diameter= 10cm*pi

The surface (area) of the cylinder is= Base * Height= 10cm*10cm*pi

 

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I’ll mark you Brainly-ist if you’re correct.
drek231 [11]

Answer:

log5 19 - log5 x

Step-by-step explanation:

log5 19/x

log ( a/b) = log a - log b

log5 19 - log5 x

5 0
3 years ago
PLEASE HELP WITH #14 AND #7 PLEASE A.S.A.P !!!
kodGreya [7K]

Answer:

7.) 16.7

Step-by-step explanation:

7). First you have to find the length of the line with the triangle that is at a 90 angle with the longest side of the triangle

Using the pythagrorem theorem a² + b² = c²

4² + b² = 5²

b² = 5² - 4²

b² = 25 - 16

b² = 9

√b² =√9

b = 3

next you do the same thing to find the missing segment of the longest side

3² + b² = 13²

b² = 169 - 9

b² = 160

b = √160 or  ≈ 12.7

12.7 + 4 = 16.7

so 16.7 is the length of that side


3 0
4 years ago
Identify y. HELP ASAP!
pickupchik [31]

Answer:

y = 2

Step-by-step explanation:

I am assuming there was some info that got left out of this that states somewhere along the line that this is right triangle inscribed in a circle or something like that.  That means that angle R is a right angle.  Therefore,

53y - 16 = 90 so

53y = 106 and

y = 2

7 0
3 years ago
Emily gives her bird 1/8 cup of bird seeds along with 1/3 cup of grains each day. How much food is given each day to the bird
ANEK [815]

Answer:

11/24 cup

Step-by-step explanation:

What you would do is add 1/8 plus 1/3. To add two fractions, each much have the same denominator. In this case, you would need to multiply 1/8 into 3/24 by multiplying 1/8 by 3 on the denominator and numerator. For 1/3, multiply each the numerator and denominator by 8 getting the fraction 8/24. Now you can line up each fraction and add the numerators, keeping the denominator at 24. That answer would be 11/24. This cannot be simplified, so the answer is 11/24 cup of food.

Whenever you are confused with assignments, it is best to tell your parent to help you or teacher the next day. Hope this helps though!

6 0
3 years ago
How do you solve simple linear equations?
Firlakuza [10]

9514 1404 393

Explanation:

The rules of equality tell you that you can do anything you like to an equation, as long as you do the same thing to both sides of the equal sign. This is the essence of Algebra, so is worth remembering. My teacher summarized it as "keep the equal sign sacred."

__

"Simple linear equations" come in several varieties. They are sometimes called "one-step", or "two-step", or "three step" linear equations, depending on how many steps are required to solve them. In what follows, we're using "x" as the variable, and the letters a, b, c, d as constants.

<u>One-step</u>

In general, the "one step" will be either an addition or a multiplication.

  x + a = b . . . . an addition equation

  ax = b . . . . . . a multiplication equation

The key in any case is to look at what is done to the variable and use an inverse operation to "undo" it. The opposite of addition is addition of the additive inverse (add the opposite). This is also called subtraction. For the addition equation, this looks like ...

  x + a - a = b - a . . . . . . add (-a) <em>to both sides </em>(or subtract 'a')

  x = b - a . . . . . . . . . . . the solution

The opposite of multiplication is multiplication by the multiplicative inverse (the reciprocal) This is also called division. For the multiplication equation, this looks like ...

  ax(1/a) = b(1/a) . . . . . multiply by (1/a) <em>on both sides</em> (or divide by 'a')

  x = b/a . . . . . . . . . . . the solution

__

<u>Two-step</u>

As with one-step linear equations, two-step equations come in some different forms.

  ax +b = c

  ax +b = cx

  a(x +b) = c

In general, the two steps are an addition step and a multiplication step, not necessarily in that order. You will notice that the first step can transform the equation to a "one-step" equation. As before, inverse operations are involved, and whatever is done is done to both sides of the equal sign.

  ax +b = c   ⇒   ax = (c -b) . . . . subtract b to get a multiplication equation

In this next, we have the variable on both sides of the equal sign. we can put the variable on one side of the equal sign by adding the opposite of the term we don't want where it is. Leaving the constant alone, we can add (-ax) to both sides to get ...

  ax +b = cx   ⇒   b = cx -ax   ⇒   b = (c -a)x

When you have numbers, you can go directly to (c-a)x by "combining terms". This is now the one-step multiplication equation.

Finally, another 2-step form is ...

  a(x +b) = c   ⇒   x +b = c/a . . . . . divide by 'a' to get an addition equation

This last equation can also be solved by using the distributive property first.

  ax +ab = c . . . . . still a 2-step equation, now of the first type

__

<u>Three-step</u>

The most typical "3-step" linear equation is of the form ...

  ax +b = cx +d

where both variables and constants are on both sides of the equal sign. As you may have noticed above, we prefer to have variables on one side and constants on the other side. So, add the opposite of the term you don't want where it is (to both sides, of course).

If we want variables on the left and constants on the right, we can add -cx and -b. The "3 steps" assume you do these as separate operations.

  ax +b -cx = cx +d -cx   ⇒   (a-c)x +b = d . . . a two-step equation

  (a-c)x +b -b = d -b    ⇒   (a-c)x = d-b . . . . a one-step multiplication equation

_____

<em>Additional comments</em>

There are some choices you can make that will tend to reduce errors. One of them involves selection of the variable term you want to eliminate (add the opposite of). Generally, if you choose the term with the lowest (most negative, left-most on the number line) coefficient, adding its opposite will result in a positive coefficient for the remaining variable term. Then when you divide by that coefficient, you're dividing by a positive number. Most folks perform arithmetic with fewer errors when they're working with positive numbers.

The general approach to any "solve for" situation is to look at what is done to the variable you're solving for. The Order of Operations is a useful lens for looking at this. When you list the operations, your "undo" sequence will start with the last operation on the list, and work backward.

<em>Further note</em>: your total comfort with doing arithmetic with any kind of numbers (integers, fractions, mixed-numbers, decimals, scientific notation, positive or negative) will aid you immensely. Always be careful with minus signs. They tend to get lost, forgotten, ignored, Be sure they don't.

8 0
3 years ago
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